Home Thermal Engineering Rankine Cycle: Processes with P-v and T-s Diagram

Rankine Cycle: Processes with P-v and T-s Diagram

Rankine Cycle

The Rankine cycle is a modified form of Carnot cycle, in which the isothermal compression (3-4) is continued unit the steam is condensed into water. A Carnot cycle, using steam as a working substance, is represented or p-v and t-s diagram as shown in the figure.

P-v diagram of Rankine cycle
T-s diagram of Rankine cycle

Consider 1kg of water at pressure P1 and absolute temperature T1 as represented by point 1 in the figure. The cycle is completed by the following four processes.

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Stages of Rankine Cycle

The following are the four stages of an ideal Rankine cycle:

  1. Isothermal expansion
  2. Adiabatic expansion
  3. Isothermal compression
  4. Warming operation

1. Isothermal Expansion

The water is isothermally converted into dry saturated steam at a constant temperature (T1) and pressure (P1). The dry state of steam is expressed in point 2. It means that the temperature T2 (i. e. at point 2) and pressure P2 (i. e. at point 2) is equal to temperature T1 and pressure P1 respectively.

This isothermal expansion is represented by curve 1-2 in p-v and t-s diagrams in Fig. We know that the heat absorbed during isothermal expansion by water dring its conversion into dry steam is its latent heat (i.e. H1 = L).

2. Adiabatic Expansion

The dry saturated steam now expands adiabatically. The pressure and temperature fall from P2 and T2 to T3 respectively with a dryness fraction x2. As no heat is supplied or rejected during this process, there is no change of entropy. The adiabatic expansion is represented by the curve 2-3 as shown in Fig.

3. Isothermal Compression

The wet steam is now isothermally compressed at constant temperature (T3) and pressure (p3) unit the whole steam is condensed into water. IT means that the temperature T4 (i.e. at point 4) and pressure P4 is equal to the temperature T3 and pressure P3 respectively.

The isothermal compression is represented by curve 3-4 on p-v and T-s diagram in Fig. The heat rejected by steam is its latent heat ( equal to x3 L3).

4. Warming Operation

The water is now warmed at constant volume from temperature T4 to T1. Its pressure also rises from P4 to P1. The heat absorbed by water dring this operation is equal to the sensible heat or liquid heat corresponding to the pressure P1 i. e. equal to sensible heat at point 1 minus sensible heat at point 4 (i.e. equal to h1- h4).

But sensible heat at point 4 is equal to sensible heat at point3. Thus heat absorbed during warming operation is equal to (h1-h3).

= Heat absorbed during isothermal expansion+ Heat absorbed during the warming operation

And heat rejected during the cycle

= Heat absorbed – Heat rejected

And efficiency (also called Rankine efficiency),

Note on Rankine Cycle

If the equation of steam (2-3) is not adiabatic and follows the general law pvn = constant, then work done during the process will not be (H1 – H3). The work done in this case will be given by the relation:

That’s it. Thank you so much for reading in our blog. If you have any questions about the “Rankine Cycle” ask in the comments section. If you like this article share with your friends.

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Saif M
Saif M. is a Mechanical Engineer by profession. He completed his engineering studies in 2014 and is currently working in a large firm as Mechanical Engineer. He is also an author and editor at theengineerspost.com


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